document.write( "Question 593296: the length of sallys garden is 4 meters greater than 3 times the width. the perimeter of her garden is 72 meters. what is the length of her garden?
\n" ); document.write( "L=4+3(w)?????
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Algebra.Com's Answer #376367 by Sarpi(32)\"\" \"About 
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\n" ); document.write( "The garden has a rectangular shape. Therefore the perimeter (P) = 2(L+W); where P= 72, L = 4 + 3W and W is not known.\r
\n" ); document.write( "\n" ); document.write( "P = 2(L+W)
\n" ); document.write( "P = 2L+ 2W
\n" ); document.write( "72 = 2(4+3W) + 2W
\n" ); document.write( "72 = 8 + 6W + 2W
\n" ); document.write( "72 = 8 + 8W
\n" ); document.write( "72 - 8 = 8W
\n" ); document.write( "64 = 8W
\n" ); document.write( "W = 64/8
\n" ); document.write( "W = 8 meters.\r
\n" ); document.write( "\n" ); document.write( "Therefore, the length = 4 + 3*8 = 28 meters.\r
\n" ); document.write( "\n" ); document.write( "Verification:
\n" ); document.write( "P = 2(L+W)
\n" ); document.write( "p = 2(28+8)
\n" ); document.write( "P = 72 meters.
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