document.write( "Question 593544: 5x^2-x=4x^2+12 \n" ); document.write( "
Algebra.Com's Answer #376357 by nerdybill(7384)\"\" \"About 
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5x^2-x=4x^2+12
\n" ); document.write( "x^2-x=12
\n" ); document.write( "x^2-x-12=0
\n" ); document.write( "(x+3)(x-4) = 0
\n" ); document.write( "x = {-3, 4}
\n" ); document.write( "
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