document.write( "Question 55441: To whom may it concern,\r
\n" ); document.write( "\n" ); document.write( "I have this tricky question to solve.\r
\n" ); document.write( "\n" ); document.write( "If x + 2y = -2 and x – 2y = 18, find the value of x^2 + 4y^2.\r
\n" ); document.write( "\n" ); document.write( "According to my teacher, the answer is 164 but how ?\r
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\n" ); document.write( "\n" ); document.write( "Please help. Thanks.\r
\n" ); document.write( "\n" ); document.write( "CH Lam
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Algebra.Com's Answer #37632 by tutorcecilia(2152)\"\" \"About 
You can put this solution on YOUR website!
Remember that y=y and x=x, than
\n" ); document.write( "Solve for y (or x) in each equation:
\n" ); document.write( "x + 2y = -2 [solve for y]
\n" ); document.write( "y=-1/2x-1
\n" ); document.write( ".
\n" ); document.write( "x – 2y = 18 [solve for y]
\n" ); document.write( "y=1/2x-9
\n" ); document.write( ".
\n" ); document.write( "Since y=y, than
\n" ); document.write( "-1/2x-1=1/2x-9 [Solve for x]
\n" ); document.write( "1x=8
\n" ); document.write( "x=8
\n" ); document.write( ".
\n" ); document.write( "Plugging (x=8) back into either of the original equations:
\n" ); document.write( "x + 2y = -2
\n" ); document.write( "(8)+2y=-2 [Solve for y]
\n" ); document.write( "y=-10/2
\n" ); document.write( "y=-5
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "Plug both values (x=8) and (y=-5) into the problem:
\n" ); document.write( "x^2+4y^2
\n" ); document.write( "(8)^2+4(-5)^2
\n" ); document.write( "64+4(25)
\n" ); document.write( "64+100
\n" ); document.write( "164
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