document.write( "Question 55457: Find the measure of an angle such that the difference between the measures of its supplement and three times its complement is 4 degrees \n" ); document.write( "
Algebra.Com's Answer #37630 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! Find the measure of an angle such that the difference between the measures of its supplement and three times its complement is 4 degrees. \n" ); document.write( "An angle is:x \n" ); document.write( "Then an angle's supplement is:180-x \n" ); document.write( "Then an angle's complement is:90-x \n" ); document.write( "Difference means subtract. \n" ); document.write( "3 times means multiply by 3. \n" ); document.write( "is means =. \n" ); document.write( "(180-x)-3(90-x)=4 \n" ); document.write( "180-x-270+3x=4 \n" ); document.write( "-90+2x=4 \n" ); document.write( "90-90+2x=4+90 \n" ); document.write( "2x=94 \n" ); document.write( "2x/2=94/2 \n" ); document.write( "x=47 \n" ); document.write( "The angle is 47 degrees. \n" ); document.write( "Happy Calculating!!! \n" ); document.write( " \n" ); document.write( " |