document.write( "Question 593321: Larry's father had to travel to a neighboring city 385 miles away for a work project. If he left at 8 a.m. and traveled at a speed of 55 mph, how far would he be at 12 noon? \n" ); document.write( "
Algebra.Com's Answer #376281 by jim_thompson5910(35256)\"\" \"About 
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From 8 am to 12 noon is 12-8 = 4 hours. So t = 4\r
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\n" ); document.write( "\n" ); document.write( "His speed is 55 mph, so r = 55\r
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\n" ); document.write( "\n" ); document.write( "Plug these values into d = rt to find your answer\r
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\n" ); document.write( "\n" ); document.write( "d = rt\r
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\n" ); document.write( "\n" ); document.write( "d = 55*4\r
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\n" ); document.write( "\n" ); document.write( "d = 220\r
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\n" ); document.write( "\n" ); document.write( "So he traveled 220 miles in the four hour time span\r
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\n" ); document.write( "\n" ); document.write( "So he's now 385 - 220 = 165 miles away from his destination.
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