document.write( "Question 593321: Larry's father had to travel to a neighboring city 385 miles away for a work project. If he left at 8 a.m. and traveled at a speed of 55 mph, how far would he be at 12 noon? \n" ); document.write( "
Algebra.Com's Answer #376281 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! From 8 am to 12 noon is 12-8 = 4 hours. So t = 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "His speed is 55 mph, so r = 55\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plug these values into d = rt to find your answer\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "d = rt\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "d = 55*4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "d = 220\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So he traveled 220 miles in the four hour time span\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So he's now 385 - 220 = 165 miles away from his destination. \n" ); document.write( " |