document.write( "Question 593136: Suppose $6,500 is divided into two bank accounts. One account pays 10% simple interest per year and the other pays 4.6%. After two years there is a total of $1000 in interest between the two accounts. How much was invested into the bank account that pays 10% simple interest (rounded to the nearest cent)? \n" ); document.write( "

Algebra.Com's Answer #376210 by mananth(16946) $\"\"$ $\"About$

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Bank I 10.00% per annum ---x
\n" ); document.write( "Bank II 4.60% per annum ---y
\n" ); document.write( "
\n" ); document.write( "x + 1 y= 6500 ------------------------1
\n" ); document.write( "10.00% x + 4.60% y= 500
\n" ); document.write( "Multiply by 100
\n" ); document.write( "10 x + 4.6 y= = 50000.00 --------2
\n" ); document.write( "Multiply (1) by -10
\n" ); document.write( "we get
\n" ); document.write( "-10x-10y=-65000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "-5.4 y= = -15000
\n" ); document.write( "divide by -5.4
\n" ); document.write( "y = 2777.78 Bank I 4.60%
\n" ); document.write( "Balance 3722.22 Bank II 10.00%
\n" ); document.write( "CHECK
\n" ); document.write( "2777.78 --------- 4.60% ------- 127.78
\n" ); document.write( "3722.22 ------- 10.00% ------- 372.22
\n" ); document.write( "Total -------------- 500.00
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