document.write( "Question 593014: What is the focus, vertex, axis of symmetry and directrix of the parabola equation y2-8y+16x-64=0 \n" ); document.write( "
Algebra.Com's Answer #376191 by lwsshak3(11628)\"\" \"About 
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What is the focus, vertex, axis of symmetry and directrix of the parabola equation
\n" ); document.write( "y2-8y+16x-64=0
\n" ); document.write( "complete the square
\n" ); document.write( "(y^2-8y+16)+16x-64-16=0
\n" ); document.write( "(y-4)^2+16x-80=0
\n" ); document.write( "(y-4)^2=-16x+80
\n" ); document.write( "(y-4)^2=-16(x-5)
\n" ); document.write( "This is an equation for a parabola that open leftwards of the standard form: (y-k)^2=-4p(x-h), (h,k)=(x,y) coordinates of the vertex.
\n" ); document.write( "For given parabola:
\n" ); document.write( "4p=16
\n" ); document.write( "p=4
\n" ); document.write( "vertex: (5,4)
\n" ); document.write( "axis of symmetry: y=4
\n" ); document.write( "focus: (1,4) (p units to left of vertex on axis of symmetry)
\n" ); document.write( "directrix: x=9 (p units to right of vertex on axis of symmetry)\r
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