document.write( "Question 593015: Find an equation for the parabola with focus (4,-6) and vertex at (3, -6) \n" ); document.write( "
Algebra.Com's Answer #376190 by lwsshak3(11628)\"\" \"About 
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Find an equation for the parabola with focus (4,-6) and vertex at (3, -6)
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\n" ); document.write( "Standard form of equation for a parabola that opens rightwards: (y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of vertex.
\n" ); document.write( "For given parabola:
\n" ); document.write( "vertex: (3,-6)
\n" ); document.write( "axis of symmetry: y=-6
\n" ); document.write( "p=1 (distance from focus to vertex on axis of symmetry)
\n" ); document.write( "4p=4
\n" ); document.write( "Equation of parabola:
\n" ); document.write( "(y+6)^2=4(x-3)
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