document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=593062>Question 593062</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has 300mL of a solution that is 2/3 acid, She wants to make a solution that is 3/4 acid. How much acid should she add to the original solution. Show work please :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #376186 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=376186\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     A chemist has 300mL of a solution that is 2/3 acid, She wants to make a solution that is 3/4 acid. How much acid should she add to the original solution. .<BR>\n" );
document.write( "Let x = amount (mL) acid added <BR>\n" );
document.write( "then<BR>\n" );
document.write( "x + (2/3)(300) = (3/4)(300 + x)<BR>\n" );
document.write( "multiplying both sides by 12:<BR>\n" );
document.write( "12x + (8)(300) = (9)(300 + x)<BR>\n" );
document.write( "12x + 2400 = 2700 + 9x<BR>\n" );
document.write( "3x + 2400 = 2700<BR>\n" );
document.write( "3x = 300<BR>\n" );
document.write( "x = 300 mL\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );