document.write( "Question 592978: consider the line y= -9x+7
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\n" ); document.write( "\n" ); document.write( "Find the equation of the line that is perpendicular to this line and passes
\n" ); document.write( "through the point (-3,-5)
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Algebra.Com's Answer #376139 by mananth(16946)\"\" \"About 
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PARALLEL
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\n" ); document.write( "y = -9 x + 7
\n" ); document.write( "Divide by 1
\n" ); document.write( " y = -9 x + 7
\n" ); document.write( "Compare this equation with y=mx+b
\n" ); document.write( "slope m = -9
\n" ); document.write( "The slope of a line parallel to the above line will be the same
\n" ); document.write( "The slope of the required line will be -9
\n" ); document.write( "m= -9 ,point ( -3 , -5 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "-5=27+b
\n" ); document.write( "b= -32
\n" ); document.write( "m= -9
\n" ); document.write( "Plug value of the slope and b in y = mx +b
\n" ); document.write( "The required equation isy=-9x-32 \r
\n" ); document.write( "\n" ); document.write( "PERPENDICULAR TO A LINE \r
\n" ); document.write( "\n" ); document.write( "y = -9 x + 7
\n" ); document.write( "Divide by 1
\n" ); document.write( " y = -9 x + 7
\n" ); document.write( "Compare this equation with y=mx+b, m= slope & b= y intercept
\n" ); document.write( "slope m = -9
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal 1/9
\n" ); document.write( "m1*m2=-1
\n" ); document.write( "The slope of the required line will be 1/9
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\n" ); document.write( "m= 1/9 ,point ( -3 , -5 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "-5 = - 1/ 3 + b
\n" ); document.write( "b= -14/3
\n" ); document.write( "m= 1/9
\n" ); document.write( "The required equation is y = 1/ 9x-14/ 3
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