document.write( "Question 592481: evaluate the limit \r
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document.write( "lim x/arctan(5x)
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document.write( "x->0\r
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document.write( "is it 1?
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document.write( "x=0
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document.write( "arcsin is cos(0)/sin(0)=1/0
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document.write( "so 0/1/0 is..... \n" );
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Algebra.Com's Answer #376118 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! If you substitute a zero for x into your expression you end up with \n" ); document.write( "So we find the derivatives of x and arctan(5x): \n" ); document.write( "The derivative of x is 1. and the derivative of arctan(5x) (remembering to use the chain rule) is \n" ); document.write( "We can now find the limit of the original ratio by finding the limit of the ratio of these derivatives: \n" ); document.write( "lim \n" ); document.write( "x->0 \n" ); document.write( "The fraction simplifies to: \n" ); document.write( "lim \n" ); document.write( "x->0 \n" ); document.write( "Substituting a zero for x we get a limit of 1/5. \n" ); document.write( " \n" ); document.write( " |