document.write( "Question 592875: if the length of the legs of a right triangle are 5 and 7, what is the length of the hypotenuse? \n" ); document.write( "
Algebra.Com's Answer #376110 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "We basically have this triangle set up:\r
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\n" ); document.write( "\n" ); document.write( "To find the unknown length, we need to use the Pythagorean Theorem.\r
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\n" ); document.write( "\n" ); document.write( "Remember, the Pythagorean Theorem is \"a%5E2%2Bb%5E2=c%5E2\" where \"a\" and \"b\" are the legs of a triangle and \"c\" is the hypotenuse.\r
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\n" ); document.write( "\n" ); document.write( "Since the legs are \"5\" and \"7\" this means that \"a=5\" and \"b=7\"\r
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\n" ); document.write( "\n" ); document.write( "Also, since the hypotenuse is \"x\", this means that \"c=x\".\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2%2Bb%5E2=c%5E2\" Start with the Pythagorean theorem.\r
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\n" ); document.write( "\n" ); document.write( "\"5%5E2%2B7%5E2=x%5E2\" Plug in \"a=5\", \"b=7\", \"c=x\" \r
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\n" ); document.write( "\n" ); document.write( "\"25%2B7%5E2=x%5E2\" Square \"5\" to get \"25\".\r
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\n" ); document.write( "\n" ); document.write( "\"25%2B49=x%5E2\" Square \"7\" to get \"49\".\r
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\n" ); document.write( "\n" ); document.write( "\"74=x%5E2\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=74\" Rearrange the equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x=sqrt%2874%29\" Take the square root of both sides. Note: only the positive square root is considered (since a negative length doesn't make sense).\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=sqrt%2874%29\" which approximates to \"x=8.602\".\r
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\n" ); document.write( "\n" ); document.write( "So the hypotenuse is roughly 8.602 units long.
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