document.write( "Question 592834: solve for x: \"+-5x%5E2=+12-3x+\" \n" ); document.write( "
Algebra.Com's Answer #376089 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"+-5x%5E2=+12-3x+\" Start with the given equation.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"+0=+12-3x%2B5x%5E2+\" Add \"5x%5E2\" to both sides\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"0+=+5x%5E2-3x%2B12\" Rearrange the terms.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"5x%5E2-3x%2B12+=+0\" Flip the equation.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Notice that the quadratic \"5x%5E2-3x%2B12\" is in the form of \"Ax%5E2%2BBx%2BC\" where \"A=5\", \"B=-3\", and \"C=12\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for \"x\":\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%28-3%29+%2B-+sqrt%28+%28-3%29%5E2-4%285%29%2812%29+%29%29%2F%282%285%29%29\" Plug in \"A=5\", \"B=-3\", and \"C=12\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28+%28-3%29%5E2-4%285%29%2812%29+%29%29%2F%282%285%29%29\" Negate \"-3\" to get \"3\". \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28+9-4%285%29%2812%29+%29%29%2F%282%285%29%29\" Square \"-3\" to get \"9\". \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28+9-240+%29%29%2F%282%285%29%29\" Multiply \"4%285%29%2812%29\" to get \"240\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28+-231+%29%29%2F%282%285%29%29\" Subtract \"240\" from \"9\" to get \"-231\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28+-231+%29%29%2F%2810%29\" Multiply \"2\" and \"5\" to get \"10\". \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+i%2Asqrt%28231%29%29%2F%2810%29\" Simplify the square root (note: If you need help with simplifying square roots, check out this solver) \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%283%2Bi%2Asqrt%28231%29%29%2F%2810%29\" or \"x+=+%283-i%2Asqrt%28231%29%29%2F%2810%29\" Break up the expression. \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the solutions are \"x+=+%283%2Bi%2Asqrt%28231%29%29%2F%2810%29\" or \"x+=+%283-i%2Asqrt%28231%29%29%2F%2810%29\"
\n" ); document.write( "
\n" );