document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=592781>Question 592781</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3x+75 + x + y = 180 <BR>\n" );
document.write( "the x and the y are supposed to help me find the area of a square.<BR>\n" );
document.write( "2x + 15 and y are the sides of the square. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #376065 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=376065\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the sides of a square are equal; so, 2x + 15 = y\r<BR>\n" );
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document.write( "substituting ___ 3x + 75 + x + 2x + 15 = 180\r<BR>\n" );
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document.write( "solve for x, then substitute back to find y </SPAN>\n" );
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