document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=592710>Question 592710</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One side of a right triangle measures 6 meters. If the hypotenuse measures 10 meters, what is the lenght of the third side? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #376026 by </B><A HREF=/tutors/aboutme.mpl?userid=mamiya><B>mamiya(56)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mamiya><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=376026\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be the side we are looking for, y the side that is 6 and z the hypotenuse\r<BR>\n" );
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document.write( "We know by the Pythagorean Theorem that ,  <BR>\n" );
document.write( " z^2  = x^2 + y^2     -->  x^2 =  z^2 - y^2  <BR>\n" );
document.write( "                     -->  x =  sqrt( z^2 - y^2)   ( x can't be a negative number)<BR>\n" );
document.write( "                    -->   x = sqrt( 10^2 - 6^2)  <BR>\n" );
document.write( "                            = sqrt( 100-36)<BR>\n" );
document.write( "                            = sqrt( 64)<BR>\n" );
document.write( "                            =8\r<BR>\n" );
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document.write( "so the third side is 8 meters<BR>\n" );
document.write( "                     </SPAN>\n" );
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