document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=592700>Question 592700</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the dimension of a rectangle whose perimeter is 34cm and the area is 66cm square? </SPAN>\n" );
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document.write( "Let L be the length and, W the width <BR>\n" );
document.write( "  We know that the perimeter of a rectangle is  2L + 2W , and that its area is  LW\r<BR>\n" );
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document.write( " So, we have :  2L + 2W =  34  -->   L + W = 17<BR>\n" );
document.write( "                LW = 66              LW=66\r<BR>\n" );
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document.write( " At this point, there are many ways of solving it.<BR>\n" );
document.write( "  <BR>\n" );
document.write( "  First, let's use the easiest way but sometimes the longest . <BR>\n" );
document.write( "   find all the two numbers whose product is 66,   <BR>\n" );
document.write( "we have: 1 and 66,  2 and 33,  3 and 22,   6 and 11<BR>\n" );
document.write( "   Now, look for the two combination in which the two numbers add up to 17<BR>\n" );
document.write( " The only combination is 6 and 11 . So, the dimension are 6 and 11\r<BR>\n" );
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document.write( "The other way i am going to use is more complex.  <BR>\n" );
document.write( "first you need to pick one equation,  write one variant in term of the other and plug in it in the other equation.  <BR>\n" );
document.write( " i chose the first equation, L+W=17  -->  L = 17 - W<BR>\n" );
document.write( "By plugging it the other equation, we get  W( 17-W) = 66; Then , we solve for W<BR>\n" );
document.write( "    W(17-W) = 66   -->  W^2 - 17W + 66 =0\r<BR>\n" );
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document.write( "  Now we use the quadratic formula.<BR>\n" );
document.write( "W=[17 + sqrt(-17^2 -4( 1)(66))]/ 2   and    W=[17 - sqrt(-17^2 -4( 1)(66))]/<BR>\n" );
document.write( " =  (17 +  5)/2                              =(17 -  5)/2<BR>\n" );
document.write( " = 11                                        = 6<BR>\n" );
document.write( "so,  the dimensions are 11 and 6.\r<BR>\n" );
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