document.write( "Question 592619: an airplane flying into a headwind travels the 1800-mile flying distance between two cities in 3 hours and 36 minutes. On the return flight, the distance is traveled in 3 hours. Find the air speed of the plane and the speed of the wind, assuming that both remain constant. \n" ); document.write( "
Algebra.Com's Answer #376009 by lwsshak3(11628)\"\" \"About 
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an airplane flying into a headwind travels the 1800-mile flying distance between two cities in 3 hours and 36 minutes. On the return flight, the distance is traveled in 3 hours. Find the air speed of the plane and the speed of the wind, assuming that both remain constant.
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\n" ); document.write( "let x=speed of plane
\n" ); document.write( "let c=speed of wind
\n" ); document.write( "x-c =net speed into wind
\n" ); document.write( "x+c=net speed with wind
\n" ); document.write( "speed*travel time=distance
\n" ); document.write( "3 hrs and 36 min=3.6 hrs
\n" ); document.write( "..
\n" ); document.write( "(x-c)*3.6=1800
\n" ); document.write( "(x+c)*3=1800
\n" ); document.write( "..
\n" ); document.write( "3.6x-3.6c=1800
\n" ); document.write( "3.0x+3.0c=1800
\n" ); document.write( "..
\n" ); document.write( "multiply first equation by 3 and second equation by 3.6
\n" ); document.write( "10.8x-10.8c=5400
\n" ); document.write( "10.8x+10.8c=6480
\n" ); document.write( "add equations to eliminate c
\n" ); document.write( "21.6x=11880
\n" ); document.write( "x=11880/21=550 mph
\n" ); document.write( "..
\n" ); document.write( "3c=1800-3x=1800-1650=150
\n" ); document.write( "c=150/3=50 mph
\n" ); document.write( "..
\n" ); document.write( "ans:
\n" ); document.write( "speed of plane=550 mph
\n" ); document.write( "speed of wind=50 mph
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