document.write( "Question 592619: an airplane flying into a headwind travels the 1800-mile flying distance between two cities in 3 hours and 36 minutes. On the return flight, the distance is traveled in 3 hours. Find the air speed of the plane and the speed of the wind, assuming that both remain constant. \n" ); document.write( "
Algebra.Com's Answer #376009 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! an airplane flying into a headwind travels the 1800-mile flying distance between two cities in 3 hours and 36 minutes. On the return flight, the distance is traveled in 3 hours. Find the air speed of the plane and the speed of the wind, assuming that both remain constant. \n" ); document.write( "** \n" ); document.write( "let x=speed of plane \n" ); document.write( "let c=speed of wind \n" ); document.write( "x-c =net speed into wind \n" ); document.write( "x+c=net speed with wind \n" ); document.write( "speed*travel time=distance \n" ); document.write( "3 hrs and 36 min=3.6 hrs \n" ); document.write( ".. \n" ); document.write( "(x-c)*3.6=1800 \n" ); document.write( "(x+c)*3=1800 \n" ); document.write( ".. \n" ); document.write( "3.6x-3.6c=1800 \n" ); document.write( "3.0x+3.0c=1800 \n" ); document.write( ".. \n" ); document.write( "multiply first equation by 3 and second equation by 3.6 \n" ); document.write( "10.8x-10.8c=5400 \n" ); document.write( "10.8x+10.8c=6480 \n" ); document.write( "add equations to eliminate c \n" ); document.write( "21.6x=11880 \n" ); document.write( "x=11880/21=550 mph \n" ); document.write( ".. \n" ); document.write( "3c=1800-3x=1800-1650=150 \n" ); document.write( "c=150/3=50 mph \n" ); document.write( ".. \n" ); document.write( "ans: \n" ); document.write( "speed of plane=550 mph \n" ); document.write( "speed of wind=50 mph \n" ); document.write( " \n" ); document.write( " |