document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=592542>Question 592542</A>: <I><SPAN STYLE=\"word-break: break-all;\"> pure acid is to be added to 10% acid solution to obtain 90L of 53% solution. what amount of each should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #375989 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=375989\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> pure acid is to be added to 10% acid solution to obtain 90L of 53% solution. what amount of each should be used?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
document.write( "x + 0.10(90-x) = 0.53*90<BR>\n" );
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document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "100x + 10*90 - 10x = 53*90<BR>\n" );
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document.write( "90x = 43*90<BR>\n" );
document.write( "x = 43 L (amt. of pure acid to be added)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "--------------- </SPAN>\n" );
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