document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=592515>Question 592515</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In the triangle shown above A = 45°, a = 15 cm, and <BR>\n" );
document.write( "c = 8 cm. What is the approximate measure of C? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #375981 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=375981\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the law of sines.\r<BR>\n" );
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document.write( "sin(A)/a = sin(C)/c\r<BR>\n" );
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document.write( "sin(45)/15 = sin(C)/8\r<BR>\n" );
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document.write( "8*sin(45)/15 = sin(C)\r<BR>\n" );
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document.write( "8*(sqrt(2)/2)/15 = sin(C)\r<BR>\n" );
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document.write( "(4*sqrt(2))/15 = sin(C)\r<BR>\n" );
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document.write( "sin(C) = (4*sqrt(2))/15\r<BR>\n" );
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document.write( "C = arcsin( (4*sqrt(2))/15 )\r<BR>\n" );
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document.write( "C = 22.155626\r<BR>\n" );
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document.write( "So the angle C is roughly 22.155626 degrees </SPAN>\n" );
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