document.write( "Question 592377: show that the area of a square is half the product of its diagonals \n" ); document.write( "

Algebra.Com's Answer #375938 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
From the pythagorean theorem, d^2 = s^2 + s^2 = 2s^2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So d^2 = 2s^2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The area of a square with side length 's' is A = s^2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So you must take half of 2s^2 to get s^2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Therefore, the area is (d^2)/2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );