document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=592216>Question 592216</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the least integral upper bound of the zeros of the function <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=f%28x%29=x%5E3-x%5E2%2B1 ALIGN=MIDDLE  ALT=\"f%28x%29=x%5E3-x%5E2%2B1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Can you please show me step by step how to do this problem? My textbook did not explain it clearly at all, and as I use a correspondance course, I do not have a teacher I can ask for help. Any help you can give will be greatly appreciated, and if you can show me the concept clearly so that I can understand not only this problem but others like it, I would be so very grateful. Thank you and God bless you for your time! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #375918 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=375918\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We know that\r<BR>\n" );
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document.write( "f(-1) = -1<BR>\n" );
document.write( "f(0) = 1<BR>\n" );
document.write( "f(1) = 1<BR>\n" );
document.write( "f(2) = 5<BR>\n" );
document.write( "f(3) = 19\r<BR>\n" );
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document.write( "And f continually increases after x > 3 (more or less) because its derivative is positive when x > 3.\r<BR>\n" );
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document.write( "Since f is continuous everywhere, and the sign of f changes from - to + between -1 and 0, we conclude that there must be a zero in the interval -1 < x < 0. Therefore 0 is the least integral upper bound. </SPAN>\n" );
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