document.write( "Question 592133: A golf ball is hit upward with a velocity of 66 feet per second (45 mph), its height h in feet above the ground after t seconds can be modeled by .
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\n" ); document.write( "\n" ); document.write( "b. When is the height of the ball 50 feet?\r
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Algebra.Com's Answer #375853 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A golf ball is hit upward with a velocity of 66 feet per second (45 mph), its height h in feet above the ground after t seconds can be modeled by
\n" ); document.write( "h(t) = -16t^2+66t
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\n" ); document.write( "a. Determine when the ball strikes the ground.
\n" ); document.write( "The height will be zero when the ball trikes the ground:
\n" ); document.write( "Solve:
\n" ); document.write( "-16t^2+66t = 0
\n" ); document.write( "---
\n" ); document.write( "Factor:
\n" ); document.write( "(-2t)(8t-33) = 0
\n" ); document.write( "t = 0 before the ball is hit.
\n" ); document.write( "t = 33/2 = 15.5 seconds (time it hits the ground)
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\n" ); document.write( "b. When is the height of the ball 50 feet?
\n" ); document.write( "Solve:
\n" ); document.write( "-16t*2 + 66t = 50 feet
\n" ); document.write( "-16t^2 + 66t - 50 = 0
\n" ); document.write( "-2(8t^2 - 32t + 25) = 0
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\n" ); document.write( "8t^2-32t+25 = 0
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\n" ); document.write( "t = [32 +- sqrt(32^2-4*8*25)]/16
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\n" ); document.write( "t = [32 +- sqrt(224)]/16
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\n" ); document.write( "t = [32 +- sqrt(4*56)]/16
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\n" ); document.write( "t = 1.021 sec. on the way up
\n" ); document.write( "t = 1.065 sec. on the way down
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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