document.write( "Question 591676: If you reverse the digits of Johns age you get Gordens age. The difference between there two ages is Susan's age and Gordon is 10 times as old as susan. What are their ages? \n" ); document.write( "
Algebra.Com's Answer #375847 by ankor@dixie-net.com(22740)\"\" \"About 
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If you reverse the digits of Johns age you get Gordens age.
\n" ); document.write( " The difference between there two ages is Susan's age and Gordon is 10 times as old as susan. What are their ages?
\n" ); document.write( ":
\n" ); document.write( "Let John's age = 10a+b
\n" ); document.write( "then Gordan's age = 10b+a
\n" ); document.write( "Let s = Susan's age
\n" ); document.write( ":
\n" ); document.write( "\"The difference between there two ages is Susan's age\"
\n" ); document.write( "S = (10a+b)-(10b+a)
\n" ); document.write( "S = 10a - a - 10b + b
\n" ); document.write( "S = 9a - 9b
\n" ); document.write( ":
\n" ); document.write( "\"Gordon is 10 times as old as Susan.\"
\n" ); document.write( "This means the unit digit of Gordan's age = 0, then the first digit of John's age = 0, therefore:
\n" ); document.write( "a = 0
\n" ); document.write( "and
\n" ); document.write( "S = -9b, does not make much sense, does it.
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