document.write( "Question 591420: solve 4+ln(27x) = 25-2lnx \n" ); document.write( "

Algebra.Com's Answer #375841 by lwsshak3(11628) $\"\"$ $\"About$

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solve 4+ln(27x) = 25-2lnx
\n" ); document.write( "ln(27x)+2lnx=21
\n" ); document.write( "ln[(27x)(x^2)]=21
\n" ); document.write( "ln(27x^3)=21
\n" ); document.write( "convert to exponential form
\n" ); document.write( "e^21=27x^3
\n" ); document.write( "take cube root of both sides
\n" ); document.write( "3x=e^7
\n" ); document.write( "x=e^7/3 \n" ); document.write( "

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