document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=592064>Question 592064</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the solution(s) to log base 4 of 4x + log base 4 of (x+3) = 2  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #375836 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=375836\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What is the solution(s) to log base 4 of 4x + log base 4 of (x+3) = 2<BR>\n" );
document.write( "log4[(4x)(x+3)]=2<BR>\n" );
document.write( "convert to exponential form: base(4) raised to log of number(2)=number(4x)(x+3)<BR>\n" );
document.write( "4^2=(4x)(x+3)=16<BR>\n" );
document.write( "4x^2+12x=16<BR>\n" );
document.write( "4x^2+12x-16=0<BR>\n" );
document.write( "x^2+3x-4=0<BR>\n" );
document.write( "(x+4)(x-1)-0<BR>\n" );
document.write( "x=-4 (reject,x>0)<BR>\n" );
document.write( "or x=1 </SPAN>\n" );
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