document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=592058>Question 592058</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello i have been trying a few ways to try and do this sum but i dont seem to get it right.I tried it 4 different ways and im not getting a sensible answer.\r<BR>\n" );
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document.write( "this is what i did for solving linear quadratic equations but stopped because it doesnot look like im doing it right:\r<BR>\n" );
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document.write( "x^2=2y+10<BR>\n" );
document.write( "3x-y=9\r<BR>\n" );
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document.write( "Solve eq 2 for y\r<BR>\n" );
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document.write( "3x-y=9<BR>\n" );
document.write( "-y=9-3x\r<BR>\n" );
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document.write( "subs -y=9-3x<BR>\n" );
document.write( "x^2+3x=2-9<BR>\n" );
document.write( "x^2+3x=-7\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #375831 by </B><A HREF=/tutors/aboutme.mpl?userid=John10><B>John10(297)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=John10><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=John10><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=375831\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have the great idea by solving for y in the second equation but you are unfinished when you solve for y from this step:<BR>\n" );
document.write( "-y = 9 - 3x<BR>\n" );
document.write( "You have to divide both sides by -1 to solve for y:<BR>\n" );
document.write( "y = 3x - 9\r<BR>\n" );
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document.write( "Now you will substitute y = 3x - 9 into the first equation:\r<BR>\n" );
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document.write( "x^2 = 2(3x - 9)+ 10<BR>\n" );
document.write( "x^2 = 6x - 18 + 10<BR>\n" );
document.write( "x^2 - 6x + 8 = 0<BR>\n" );
document.write( "(x -4)(x-2) = 0<BR>\n" );
document.write( "x = 2 or x = 4<BR>\n" );
document.write( "Now we will substitute those two values to find two values of y:\r<BR>\n" );
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document.write( "If x =2 then  y = 3(2) - 9 = 6 - 9 = -3<BR>\n" );
document.write( "If x = 4 then y = 3(4) - 9 = 12 - 9 = 3\r<BR>\n" );
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document.write( "So we have two solutions: (2, -3) or (4, 3)\r<BR>\n" );
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document.write( "Hope it helps:)\r<BR>\n" );
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document.write( "John10 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );