document.write( "Question 591931: Find an equation of the line that passes through the point (1,-3) and is parallel to the line 8x-4y=-4.\r
\n" ); document.write( "\n" ); document.write( "a) 8x-4y=20
\n" ); document.write( "b) x-3y=-4
\n" ); document.write( "c) 8x-4y=-28
\n" ); document.write( "d) 8x+4y=-4
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Algebra.Com's Answer #375783 by nyc_function(2741)\"\" \"About 
You can put this solution on YOUR website!
We first solve 8x-4y = -4 for y.\r
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\n" ); document.write( "\n" ); document.write( "-4y = -8x - 4\r
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\n" ); document.write( "\n" ); document.write( "y = (-8x - 4)/-4\r
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\n" ); document.write( "\n" ); document.write( "y = 2x + 1\r
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\n" ); document.write( "\n" ); document.write( "We now use the point-slope formula and the slope just found. The slope is the coefficient of x in the equation y = 2x + 1. The slope is 2.\r
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\n" ); document.write( "\n" ); document.write( "Let (1,-3) = (a,b)\r
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\n" ); document.write( "\n" ); document.write( "The point-slope formula is y - b = slope(x - a).\r
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\n" ); document.write( "\n" ); document.write( "y - (-3) = 2(x - 1)\r
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\n" ); document.write( "\n" ); document.write( "y + 3 = 2x - 2\r
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\n" ); document.write( "\n" ); document.write( "y = 2x - 2 - 3\r
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\n" ); document.write( "\n" ); document.write( "y = 2x - 5\r
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\n" ); document.write( "\n" ); document.write( "The equation y = 2x - 5 is EXACTLY the same equation given in choice (a).\r
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\n" ); document.write( "\n" ); document.write( "The answer is choice (a).\r
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\n" ); document.write( "\n" ); document.write( "If you have a fax number, I can fax my answers to you for other questions that you may have. It is easier to write on paper and then fax my answers to students. If you have a fax number, send it to: nycfunction@yahoo.com\r
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