document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=591874>Question 591874</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am trying to solve logarithmic and exponential functions. However, I have gotten stuck. What is the solution to log(3x+7) + log(x-2)=1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #375761 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=375761\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> adding logs means multiplying their arguments; and one is the log of 10\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "(3x + 7)(x - 2) = 10\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "remember that logs are not defined for negative arguments </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );