document.write( "Question 591742: I have $1.45 in nickels and dimes, if the nickels had been dimes and the dimes had been nickels, I would have $1.25. How many nickels and dimes do I actually have? Please explain step by step thank you. \n" ); document.write( "
Algebra.Com's Answer #375744 by ankor@dixie-net.com(22740)\"\" \"About 
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Let n = original number of nickels
\n" ); document.write( "Let d = original number of dimes
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\n" ); document.write( "Write an equation for each statement:
\n" ); document.write( ":
\n" ); document.write( "\"I have $1.45 in nickels and dimes,\"
\n" ); document.write( ".05n + .10d = 1.45
\n" ); document.write( ":
\n" ); document.write( "\"if the nickels had been dimes and the dimes had been nickels, I would have $1.25.\"
\n" ); document.write( ".10n + .05d = 1.25
\n" ); document.write( ":
\n" ); document.write( "Multiply the 1st equation by 2, subtract the 2nd equation
\n" ); document.write( ".10n + .20d = 2.90
\n" ); document.write( ".10n + .05d = 1.25
\n" ); document.write( "-------------------- subtraction eliminates n, find d
\n" ); document.write( " 0 + .15d = 1.65
\n" ); document.write( "d = \"1.65%2F.15\"
\n" ); document.write( "d = 11 dimes originally
\n" ); document.write( ":
\n" ); document.write( "Use the 1st equation to find n, replace d with 11
\n" ); document.write( ".05n + .10(11) = 1.25
\n" ); document.write( ".05n + 1.10 = 1.25
\n" ); document.write( ".05n = 1.25 - 1.10
\n" ); document.write( ".05n = .15
\n" ); document.write( "n = \".15%2F.05\"
\n" ); document.write( "n = 3 nickels originally
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check these solutions using the statement:
\n" ); document.write( "if the nickels had been dimes and the dimes had been nickels, I would have $1.25.\"
\n" ); document.write( "3(.05) + .10(11) =
\n" ); document.write( ".15 + 1.10 = 1.25; confirms our solutions of n=3, d=11\r
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