document.write( "Question 591782: The Pendino family bought a new house 10 years ago for $128,500. The house is now worth $180,000. Assuming a steady rate of exponential growth, what was the yearly rate of appreciation in %? (using y=ab^x)
\n" ); document.write( "Work so far: 180,000=128,500b^10, then we got 1.4007=b^10.
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Algebra.Com's Answer #375729 by jim_thompson5910(35256)\"\" \"About 
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Good so far. Now take the tenth root of both sides to solve for b\r
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\n" ); document.write( "\n" ); document.write( "\"1.4007=b%5E10\"\r
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\n" ); document.write( "\n" ); document.write( "\"root%2810%2C1.4007%29=root%2810%2Cb%5E10%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"1.03427=b\"\r
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\n" ); document.write( "\n" ); document.write( "\"b+=+1.03427\"\r
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\n" ); document.write( "\n" ); document.write( "So the yearly rate of appreciation as a percentage is approximately (1.03427-1)*100 = 3.427 %
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