document.write( "Question 591708: Emily's boat goes 14 mph. Find the speed of the current in the river if she can go 8 miles downstream in the same time as she can go 6 miles upstream. \n" ); document.write( "
Algebra.Com's Answer #375709 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r\r
\n" ); document.write( "\n" ); document.write( "Let s=speed of the current
\n" ); document.write( "Emily's speed upstream=14-s
\n" ); document.write( "Her speed downstream=14+s
\n" ); document.write( "time required to go 6 miles upstream=6/(14-s)
\n" ); document.write( "time required to go 8 miles downstream=8/(14+s)
\n" ); document.write( "and we are told that these times are the same, sooooo
\n" ); document.write( "6/(14-s)=8/(14+s) multiply each term by (14-s)(14+s) or just cross-multiply and we get:
\n" ); document.write( "6(14+s)=8(14-s) or
\n" ); document.write( "3(14+s)=4(14-s)
\n" ); document.write( "42+3s=56-4s
\n" ); document.write( "7s=14
\n" ); document.write( "s=2 mph----speed of current
\n" ); document.write( "CK
\n" ); document.write( "Emily's speed upstream=14-2=12mph
\n" ); document.write( "Her speed downstream=14+2=16 mph
\n" ); document.write( "time required to go 6 mi upstream=6/12=1/2 hr
\n" ); document.write( "time required to go 8 mi downstream=8/16=1/2 hr\r
\n" ); document.write( "\n" ); document.write( "Hope this helps ---ptaylor
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