document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=591623>Question 591623</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a wire when bent into the form of a square encloses an area of 121 sq.cm. if the wire is bent in the form of a circle, then what would be the area? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #375686 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=375686\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a wire when bent into the form of a square encloses an area of 121 sq.cm. if the wire is bent in the form of a circle, then what would be the area?<BR>\n" );
document.write( "Let x = length of one side square<BR>\n" );
document.write( "then<BR>\n" );
document.write( "x^2 = 121<BR>\n" );
document.write( "x = 11 cm<BR>\n" );
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document.write( "Perimeter of square = 4*11 = 44 cm<BR>\n" );
document.write( "circumference of circle = 44 cm<BR>\n" );
document.write( "2(pi)r = 44<BR>\n" );
document.write( "(pi)r = 22<BR>\n" );
document.write( "r = 22/(pi)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "area of circle:<BR>\n" );
document.write( "(pi)r^2<BR>\n" );
document.write( "(pi)(22/(pi))^2<BR>\n" );
document.write( "(pi)(484/(pi)^2)<BR>\n" );
document.write( "484/(pi)<BR>\n" );
document.write( "154.14 square cm\r<BR>\n" );
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document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );