document.write( "Question 591477: Copying the question from test. The box below has a volume of 72ft3. Use the equation to solve for x. Finally, label the width and the height of the box.\r
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document.write( "equations x-3, x+1,and 6ft.\r
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document.write( "Hope this helps on how to solve it. Please I need it send by tonight or tomorrow. I got a test on Tues. \n" );
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Algebra.Com's Answer #375656 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The box below has a volume of 72ft3. Use the equation to solve for x. \n" ); document.write( " Finally, label the width and the height of the box. \n" ); document.write( "equations x-3, x+1, and 6 ft. \n" ); document.write( ": \n" ); document.write( "The equation will be the volume which is L * W * H, in this problem \n" ); document.write( "W = (x-3) \n" ); document.write( "L = (x+1) \n" ); document.write( "H = 6 \n" ); document.write( ": \n" ); document.write( "We could write like this \n" ); document.write( "6*(x-3)*(x+1) = 72 \n" ); document.write( "divide both sides by 6 \n" ); document.write( "(x-3)(x+1) = 72/6 \n" ); document.write( "(x-3)(x+1) = 12 \n" ); document.write( "FOIL \n" ); document.write( "x^2 + x - 3x - 3 = 12 \n" ); document.write( "Arrange as a quadratic equation \n" ); document.write( "x^2 - 2x - 3 - 12 = 0 \n" ); document.write( "x^2 - 2x - 15 = 0 \n" ); document.write( "Factors to \n" ); document.write( "(x+3)(x-5) = 0 \n" ); document.write( "Th positive solution is what we want here \n" ); document.write( "x = 5 \n" ); document.write( "then \n" ); document.write( "Width: 5-3 = 2 ft \n" ); document.write( "Length: 5+1 = 6 ft \n" ); document.write( "Height given as 6 t \n" ); document.write( ": \n" ); document.write( "Check the volume 2 * 6 * 6 = 72 cu/ft \n" ); document.write( " \n" ); document.write( " |