document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=591506>Question 591506</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are complementary. The measure of one angle is 30° more than one-half of the measure of the other. Find the measure of each angle. \r<BR>\n" );
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document.write( "Two angles are complementary. The measure of one angle is 2° more than seven times the measure of the other. Find the measure of each angle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #375643 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=375643\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+0.5x+30=90<BR>\n" );
document.write( "1.5x=90-30<BR>\n" );
document.write( "1.5x=60<BR>\n" );
document.write( "x=60/1.5<BR>\n" );
document.write( "x=40<BR>\n" );
document.write( "0.5x+30=50<BR>\n" );
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document.write( "x+7x+2=90<BR>\n" );
document.write( "8x=90-2<BR>\n" );
document.write( "8x=88<BR>\n" );
document.write( "x=88/8<BR>\n" );
document.write( "x=11<BR>\n" );
document.write( "7x+2=79 </SPAN>\n" );
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