document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=591449>Question 591449</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 4 more than twice another. The sum of the numbers is 13. Find the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #375638 by </B><A HREF=/tutors/aboutme.mpl?userid=llorton><B>llorton(14)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=llorton><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=375638\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a = the first number<BR>\n" );
document.write( "b = the second number\r<BR>\n" );
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document.write( "b = 2*a + 4<BR>\n" );
document.write( "a + b = 13\r<BR>\n" );
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document.write( "a + (2*a + 4) = 13<BR>\n" );
document.write( "a + 2*a + 4 = 13<BR>\n" );
document.write( "3*a + 4 = 13<BR>\n" );
document.write( "3*a + 4 - 4 = 13 - 4<BR>\n" );
document.write( "3*a = 9<BR>\n" );
document.write( "3*a/3 = 9/3<BR>\n" );
document.write( "a = 3<BR>\n" );
document.write( "b = 2*3 + 4<BR>\n" );
document.write( "b = 6 + 4 = 10\r<BR>\n" );
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document.write( "a + b = 3 + 10 = 13\r<BR>\n" );
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document.write( "The two numbers are 3 and 10. </SPAN>\n" );
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