document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=591299>Question 591299</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please Help me answer this homework promblem on equations. a one year old killer whale is 290 cm long the whale grows 3cm per month how many years will it take until the whale is 470 cm long? Please help thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #375558 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=375558\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = months, y = length\r<BR>\n" );
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document.write( "Equation is: y = 3x + 290\r<BR>\n" );
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document.write( "You get this by adding the initial length of 290 cm to the variable length 3x cm. For example, in month zero (the start), the length is y = 3(0)+290 = 290 and in one month, the length is y = 3(1) + 290 = 293\r<BR>\n" );
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document.write( "From here, plug in y = 470 and solve for x:\r<BR>\n" );
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document.write( "y = 3x + 290\r<BR>\n" );
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document.write( "470 = 3x + 290\r<BR>\n" );
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document.write( "470-290 = 3x\r<BR>\n" );
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document.write( "180 = 3x\r<BR>\n" );
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document.write( "180/3 = x\r<BR>\n" );
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document.write( "60 = x\r<BR>\n" );
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document.write( "x = 60\r<BR>\n" );
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document.write( "So in 60 months, or 60/12 = <font color=\"red\">5 years</font>, the whale will be 470 cm long </SPAN>\n" );
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