document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=55344>Question 55344</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I tried answering but cant come up with an answer.  Please help me to solve and check.\r<BR>\n" );
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document.write( "sqrt 2y+7+4=y \r<BR>\n" );
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document.write( "    <BR>\n" );
document.write( "\/2y+7+4=y </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #37551 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=37551\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SQRT(2Y+7+4)=Y<BR>\n" );
document.write( "SQRT(2Y+11)=Y<BR>\n" );
document.write( "NOW SQUARE BOTH SIDES<BR>\n" );
document.write( "2Y+11=Y^2 <BR>\n" );
document.write( "Y^2-2Y-11=0<BR>\n" );
document.write( "USING THE QUADRATIC EQUATION WE GET<BR>\n" );
document.write( "Y=(2+-SQRT48)/2<BR>\n" );
document.write( "Y=2+-4SQRT6)/2<BR>\n" );
document.write( "Y=1+-2SQRT6 OR<BR>\n" );
document.write( "Y=4.464<BR>\n" );
document.write( "Y=-2.464<BR>\n" );
document.write( " </SPAN>\n" );
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