document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=591111>Question 591111</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In the army kitchen there are four pots for every three pans for every 21 glasses. All together there are 476 of these items. How many pans are there?<BR>\n" );
document.write( "a=pots; b=pans; c=glasses; So, 4a + 3b + 21c = 476<BR>\n" );
document.write( "Now what?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #375490 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=375490\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In the army kitchen there are four pots for every three pans for every 21 glasses. All together there are 476 of these items. How many pans are there?<BR>\n" );
document.write( "a=pots; b=pans; c=glasses; So, 4a + 3b + 21c = 476<BR>\n" );
document.write( "Now what?<BR>\n" );
document.write( "----------------<BR>\n" );
document.write( "So, 4a + 3b + 21c = 476<BR>\n" );
document.write( "The trick is, a, b & c are integers.  You can't have 2/3 of a pot or pan.<BR>\n" );
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document.write( "4 + 3 + 21 = 28<BR>\n" );
document.write( "476/28 = 17<BR>\n" );
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document.write( "pots = 4*17 = 68<BR>\n" );
document.write( "pans = 3*17 = 51<BR>\n" );
document.write( "glasses = 21*17 = 357<BR>\n" );
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