document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=55341>Question 55341</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi guys, hope you can help me with this problem. I tried to figure it out by myself but I am completely lost. Here it is:\r<BR>\n" );
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document.write( "Kenneth recently started a new job. His starting gross monthly salary is $3200. Each year, on the anniversary of his starting date, Kenneth is promised a 7% raise.\r<BR>\n" );
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document.write( "A.If Kenneth works for 5 years, what was his gross annual income in his fifth year at work?<BR>\n" );
document.write( "B.What is the minimum of years Kenneth will have to work to earn a gross annual income of at least $60000?\r<BR>\n" );
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document.write( "Thanks in advanced!!!\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #37547 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=37547\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3200*(1.07)^5=3200*1.40<BR>\n" );
document.write( "3200*1.40=$4480 SALARY AFTER 5 YEARS.\r<BR>\n" );
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document.write( "3200(1.07}^X>=60000<BR>\n" );
document.write( "1.07^X>=60000/3200<BR>\n" );
document.write( "1.07^X>=18.75<BR>\n" );
document.write( "X=44 YEARS TO GET >=$60,000 ANNUAL SALARY<BR>\n" );
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