document.write( "Question 590855: FIND THE EQUATION OF THE PARABOLA WITH FOCUS (2,5) AND DIRECTRIX Y = 1 \n" ); document.write( "
Algebra.Com's Answer #375463 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! FIND THE EQUATION OF THE PARABOLA WITH FOCUS (2,5) AND DIRECTRIX Y = 1 \n" ); document.write( "** \n" ); document.write( "Standard form of equation for a parabola that opens upwards: (x-h)^2=4p(y-k), (h,k)=(x,y) coordinates of the vertex. \n" ); document.write( "For given parabola: \n" ); document.write( "axis of symmetry: x=2 \n" ); document.write( "x-coordinate of vertex=2 \n" ); document.write( "y-coordinate of vertex=3 (halfway between focus(5) and directrix(1) on the axis of symmetry \n" ); document.write( "vertex: (2,3) \n" ); document.write( "P=2 (distance from focus to vertex) \n" ); document.write( "4p=8 \n" ); document.write( "Equation of given parabola: \n" ); document.write( "(x-2)^2=8(y-3) \n" ); document.write( " |