document.write( "Question 590855: FIND THE EQUATION OF THE PARABOLA WITH FOCUS (2,5) AND DIRECTRIX Y = 1 \n" ); document.write( "
Algebra.Com's Answer #375463 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
FIND THE EQUATION OF THE PARABOLA WITH FOCUS (2,5) AND DIRECTRIX Y = 1
\n" ); document.write( "**
\n" ); document.write( "Standard form of equation for a parabola that opens upwards: (x-h)^2=4p(y-k), (h,k)=(x,y) coordinates of the vertex.
\n" ); document.write( "For given parabola:
\n" ); document.write( "axis of symmetry: x=2
\n" ); document.write( "x-coordinate of vertex=2
\n" ); document.write( "y-coordinate of vertex=3 (halfway between focus(5) and directrix(1) on the axis of symmetry
\n" ); document.write( "vertex: (2,3)
\n" ); document.write( "P=2 (distance from focus to vertex)
\n" ); document.write( "4p=8
\n" ); document.write( "Equation of given parabola:
\n" ); document.write( "(x-2)^2=8(y-3)
\n" ); document.write( "
\n" );