document.write( "Question 590908: You recieve a penny on January 1st, two cents the next day, four cents the next and so on,doubling every day. How long will it take to be a millionaire? Suppose you started with a nickle and doubled, how long before you were worth a million dollars? \n" ); document.write( "
Algebra.Com's Answer #375455 by Alan3354(69443)\"\" \"About 
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You recieve a penny on January 1st, two cents the next day, four cents the next and so on,doubling every day. How long will it take to be a millionaire?
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\n" ); document.write( "The total each day is \"2%5Ed+-+1\" cents.
\n" ); document.write( "$1,000,000 = 100,000,000 cents.
\n" ); document.write( "\"2%5Ed+-+1+=+100000000\"
\n" ); document.write( "\"2%5Ed+=+99999999\"
\n" ); document.write( "d*log(2) = log(99999999}
\n" ); document.write( "d = log(99999999)/log(2)
\n" ); document.write( "d =~ 26.575 days
\n" ); document.write( "--> 26 days
\n" ); document.write( "-------------------
\n" ); document.write( " Suppose you started with a nickle and doubled, how long before you were worth a million dollars?
\n" ); document.write( "$1,000,000 = 100,000,000 cents = 20,000,000 nickels
\n" ); document.write( "Amt = \"5%2A%282%5Ed+-+1%29+=+100000000\"
\n" ); document.write( "\"2%5Ed+-+1+=+20000000\"
\n" ); document.write( "\"2%5Ed+=+19999999\"
\n" ); document.write( "d*log(2) = log(19999999}
\n" ); document.write( "d = log(19999999)/log(2)
\n" ); document.write( "d =~ 24.25 days
\n" ); document.write( "--> 25 days
\n" ); document.write( "----------------
\n" ); document.write( "Not much difference. If you multiply by 5 each day, it was reduce the time more drastically.
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