document.write( "Question 590599: 2/5x+7=9 \n" ); document.write( "
Algebra.Com's Answer #375447 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"%282%2F5%29x%2B7=9\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"5%28%282%2Fcross%285%29%29x%2B7%29=5%289%29\" Multiply both sides by the LCD \"5\" to clear any fractions.\r
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\n" ); document.write( "\n" ); document.write( "\"2x%2B35=45\" Distribute and multiply.\r
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\n" ); document.write( "\n" ); document.write( "\"2x=45-35\" Subtract \"35\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"2x=10\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2810%29%2F%282%29\" Divide both sides by \"2\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=5\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=5\" \r
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