document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=590987>Question 590987</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The question is and it doesnt make sense to me.<BR>\n" );
document.write( "A orange tree at 7ft tall products 18pounds of oranges. At 12ft it products 62pounds. If you minus 62-18=44, 12-7=5 so it is 44/5. Use the equation 44/5(h-7) to figure out a 18ft tree and 20ft tree and how many pounds they have. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #375416 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=375416\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the derived equation doesn't work for the 7ft or 12 ft tree, so why should it work for the others?\r<BR>\n" );
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document.write( "if a linear relation is correct, the 44/5 is the slope (lbs of oranges per ft of tree)<BR>\n" );
document.write( "___ there also may be a \"fudge factor\" (y-intercept) that comes into play\r<BR>\n" );
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document.write( "18 = (44/5)(7) + ? ___ 18 = 308/5 + ? ___ -43.6 = ?\r<BR>\n" );
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document.write( "62 = (44/5)(12) - 43.6 ___ 62 = 528/5 - 43.6 ___ 62 = 105.6 - 43.6 ___ 62 = 62\r<BR>\n" );
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document.write( "(lb of oranges) = (44/5)(ft of tree) - 43.6 </SPAN>\n" );
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