document.write( "Question 590971: to do certain work alone 'A' takes 4 hrs,'B' takes 5 hrs and c takes 6 hrs.how long would A and b together take to do a work which C can do in 4 n half hours? \n" ); document.write( "
Algebra.Com's Answer #375412 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
\"A\" is not the same as \"a\"
\n" ); document.write( "This is math. Be more precise.
\n" ); document.write( "[x/4+x/5+x/6=1
\n" ); document.write( "x=60/37
\n" ); document.write( "Together all three can do the first job in 60/37 hours. \r
\n" ); document.write( "\n" ); document.write( "a does 15/37 of the first job
\n" ); document.write( "b does 12/37 of the first job
\n" ); document.write( "c does 10/37 of the first job]\r
\n" ); document.write( "\n" ); document.write( "second job
\n" ); document.write( "4.5/6=3/4
\n" ); document.write( "c does the job in 3/4 of the time.\r
\n" ); document.write( "\n" ); document.write( "3/4 of 4=3
\n" ); document.write( "a does the job in 3 hours
\n" ); document.write( "3/4 of 5=15/4=3 3/4
\n" ); document.write( "b does the job in 3.75 hours
\n" ); document.write( "y/3 +y/3.75=1
\n" ); document.write( "Together a and b do the second job in 1 2/3 hours\r
\n" ); document.write( "\n" ); document.write( " \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );