document.write( "Question 55312: This is a Poisson probability distribution problem. I thought it was easy but I can't get the answer right. I hope you'll find time to help me. Thanks.\r
\n" ); document.write( "\n" ); document.write( "A Statistics Professor finds that when she schedules an office hour for student help, an average of 2 students arrive. Find the the probability that in a randomly selected hour, the number of student arrival is 5. Give the answer as a decimal value with 4 places of precision and no leading 0.\r
\n" ); document.write( "\n" ); document.write( "P(x) = 2/8 = 0.25 ( I used 8 as I thought it meant 8 office hours)\r
\n" ); document.write( "\n" ); document.write( "P(x) = (0.25)^2 * 2.71828^-0.25/5!\r
\n" ); document.write( "\n" ); document.write( " = 0.0625 * .779/120\r
\n" ); document.write( "\n" ); document.write( " = .0004057 (or should it be .4057)\r
\n" ); document.write( "\n" ); document.write( "Again, thanks
\n" ); document.write( "

Algebra.Com's Answer #37540 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
I'm using the following formula:
\n" ); document.write( "P(n,T) =(mu*T)^n][e^(-muT)]/n!
\n" ); document.write( "Your mu is 2; your T = 1 hr. ; your n=5
\n" ); document.write( "
\n" ); document.write( "Actual arrivals in one hour were 2.
\n" ); document.write( "P(5 arrivals in one hour) = (2(1))^5 e^(-2(1))/5!
\n" ); document.write( "=[32e^-2]/120
\n" ); document.write( "=[32]/[120e^2]
\n" ); document.write( "=0.0361
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" ); document.write( "
\n" );