document.write( "Question 55312: This is a Poisson probability distribution problem. I thought it was easy but I can't get the answer right. I hope you'll find time to help me. Thanks.\r
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document.write( "A Statistics Professor finds that when she schedules an office hour for student help, an average of 2 students arrive. Find the the probability that in a randomly selected hour, the number of student arrival is 5. Give the answer as a decimal value with 4 places of precision and no leading 0.\r
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document.write( "P(x) = 2/8 = 0.25 ( I used 8 as I thought it meant 8 office hours)\r
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document.write( "P(x) = (0.25)^2 * 2.71828^-0.25/5!\r
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document.write( " = 0.0625 * .779/120\r
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document.write( " = .0004057 (or should it be .4057)\r
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document.write( "Again, thanks \n" );
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Algebra.Com's Answer #37540 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! I'm using the following formula: \n" ); document.write( "P(n,T) =(mu*T)^n][e^(-muT)]/n! \n" ); document.write( "Your mu is 2; your T = 1 hr. ; your n=5 \n" ); document.write( " \n" ); document.write( "Actual arrivals in one hour were 2. \n" ); document.write( "P(5 arrivals in one hour) = (2(1))^5 e^(-2(1))/5! \n" ); document.write( "=[32e^-2]/120 \n" ); document.write( "=[32]/[120e^2] \n" ); document.write( "=0.0361 \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |