document.write( "Question 590969: A man is presently 4 times the age of his son. He learned that 3 years ago he was 7 times the age of his son. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #375395 by alicealc(293)![]() ![]() ![]() You can put this solution on YOUR website! let: \n" ); document.write( "Man's age = m years old \n" ); document.write( "Son's age = s years old\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "m = 4*s\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "m - 3 = 7*(s - 3) \n" ); document.write( "4s - 3 = 7s - 21 \n" ); document.write( "21 - 3 = 7s - 4s \n" ); document.write( "18 = 3s \n" ); document.write( "s = 18/3 s = 6 \n" ); document.write( "m = 4s = 4*6 = 24\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, now, the man is 24 years old, and his son is 6 years old\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |