document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=590944>Question 590944</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the bearing of A to B is 138°,then what is the bearing of B to A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #375378 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=375378\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the bearing of A to B is 138°,then what is the bearing of B to A?<BR>\n" );
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document.write( "138 + 180 = 318 degs<BR>\n" );
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document.write( "If it's less than or  =180, add 180 to get the reciprocal heading.<BR>\n" );
document.write( "If it's more, subtract 180.<BR>\n" );
document.write( "North is 360 degs. </SPAN>\n" );
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