document.write( "Question 590916: Is there an easy way to understand how to work these? Would someone please show me?\r
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Algebra.Com's Answer #375352 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"5x%5E3-15x%5E2-4x%2B12\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"%285x%5E3-15x%5E2%29%2B%28-4x%2B12%29\" Group the terms in two pairs\r
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\n" ); document.write( "\n" ); document.write( "\"5x%5E2%28x-3%29-4%28x-3%29\" Factor out the GCF \"5x%5E2\" out of the first group. Factor out the GCF \"-4\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%285x%5E2-4%29%28x-3%29\" Since we have the common term \"x-3\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"5x%5E3-15x%5E2-4x%2B12\" factors to \"%285x%5E2-4%29%28x-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"5x%5E3-15x%5E2-4x%2B12=%285x%5E2-4%29%28x-3%29\" for all values of x.\r
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