document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=590753>Question 590753</A>: <I><SPAN STYLE=\"word-break: break-all;\"> there is three more quaters than dimes but twice as many nickles as quaters the total is 3.75 how would you write this in an algebreic expression? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #375315 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=375315\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> there are three unknowns (nickels, dimes, quarters), so you need three equations\r<BR>\n" );
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document.write( "5n + 10d + 25q = 375\r<BR>\n" );
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document.write( "q = d + 3 ___ q - 3 = d\r<BR>\n" );
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document.write( "n = 2q\r<BR>\n" );
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document.write( "you can solve the system by substituting ___ 5(2q) + 10(q - 3) + 25q = 375 ___ 10q + 10q - 30 + 25q = 375 ___ 45q = 405\r<BR>\n" );
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document.write( "solve for q, and then substitute back to find n and d </SPAN>\n" );
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