document.write( "Question 590846: -3x+12=1+5x+10-6x \n" ); document.write( "
Algebra.Com's Answer #375307 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"-3x%2B12=1%2B5x%2B10-6x\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"-3x%2B12=-x%2B11\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"-3x=-x%2B11-12\" Subtract \"12\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-3x%2Bx=11-12\" Add \"x\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-2x=11-12\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"-2x=-1\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-1%29%2F%28-2%29\" Divide both sides by \"-2\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=1%2F2\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=1%2F2\" \r
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\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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